A 0.4 kg ball is pushed with a 2 N force along a frictionless surface for 3 seconds. What is the change in velocity (Δv)?

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Multiple Choice

A 0.4 kg ball is pushed with a 2 N force along a frictionless surface for 3 seconds. What is the change in velocity (Δv)?

Explanation:
This question uses the idea that a constant force applied over time produces impulse, which changes the velocity. The impulse equals force times time, and on a frictionless surface the change in velocity equals impulse divided by mass: Δv = (F × t) / m. Calculate the impulse: F × t = 2 N × 3 s = 6 N·s. Then Δv = 6 N·s / 0.4 kg = 15 m/s. You can also see it by finding the acceleration first: a = F/m = 2 / 0.4 = 5 m/s^2, and over 3 seconds the velocity changes by Δv = a × t = 5 × 3 = 15 m/s. So the change in velocity is 15 m/s.

This question uses the idea that a constant force applied over time produces impulse, which changes the velocity. The impulse equals force times time, and on a frictionless surface the change in velocity equals impulse divided by mass: Δv = (F × t) / m.

Calculate the impulse: F × t = 2 N × 3 s = 6 N·s. Then Δv = 6 N·s / 0.4 kg = 15 m/s.

You can also see it by finding the acceleration first: a = F/m = 2 / 0.4 = 5 m/s^2, and over 3 seconds the velocity changes by Δv = a × t = 5 × 3 = 15 m/s.

So the change in velocity is 15 m/s.

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