A 1.5 kg object experiences a net force of 4 N. What is its acceleration? If the same force is applied to a 6 kg object, what is the acceleration?

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Multiple Choice

A 1.5 kg object experiences a net force of 4 N. What is its acceleration? If the same force is applied to a 6 kg object, what is the acceleration?

Explanation:
Acceleration is found using a = F/m, so with the same net force, a lighter object speeds up more. For the 1.5 kg object, a = 4 N / 1.5 kg ≈ 2.666... m/s^2, about 2.67 m/s^2. For the 6 kg object, a = 4 N / 6 kg ≈ 0.666... m/s^2, about 0.67 m/s^2. This matches the set of values: 2.67 m/s^2 for the lighter mass and 0.67 m/s^2 for the heavier mass, illustrating that acceleration is inversely related to mass when the net force is fixed.

Acceleration is found using a = F/m, so with the same net force, a lighter object speeds up more. For the 1.5 kg object, a = 4 N / 1.5 kg ≈ 2.666... m/s^2, about 2.67 m/s^2. For the 6 kg object, a = 4 N / 6 kg ≈ 0.666... m/s^2, about 0.67 m/s^2. This matches the set of values: 2.67 m/s^2 for the lighter mass and 0.67 m/s^2 for the heavier mass, illustrating that acceleration is inversely related to mass when the net force is fixed.

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