A ball is dropped from rest. Neglect air resistance. What is the velocity after t = 3 s? (g = 9.8 m/s^2 downward)

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Prepare for the Year 10 Force and Motion Test. Utilize flashcards and multiple-choice questions with clear hints and explanations to ensure success. Equip yourself for excellence on your exam!

Multiple Choice

A ball is dropped from rest. Neglect air resistance. What is the velocity after t = 3 s? (g = 9.8 m/s^2 downward)

Explanation:
Falling with no air resistance means a constant downward acceleration of 9.8 m/s^2. Starting from rest, the velocity after time t is v = v0 + a t. With v0 = 0 and a = 9.8 m/s^2 downward, after 3 seconds v = 0 + (9.8)(3) = 29.4 m/s downward. So the speed is 29.4 m/s and the direction is downward toward the ground. The other options don’t fit: 29.4 m/s upward would require motion opposite to the gravity acting downward; 9.8 m/s downward is the speed after 1 second, not 3; 44.1 m/s downward would correspond to 4.5 seconds of fall.

Falling with no air resistance means a constant downward acceleration of 9.8 m/s^2. Starting from rest, the velocity after time t is v = v0 + a t. With v0 = 0 and a = 9.8 m/s^2 downward, after 3 seconds v = 0 + (9.8)(3) = 29.4 m/s downward. So the speed is 29.4 m/s and the direction is downward toward the ground. The other options don’t fit: 29.4 m/s upward would require motion opposite to the gravity acting downward; 9.8 m/s downward is the speed after 1 second, not 3; 44.1 m/s downward would correspond to 4.5 seconds of fall.

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