A ball is thrown upward with initial speed 15 m/s. Using g = 9.8 m/s^2, what is the maximum height reached?

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Multiple Choice

A ball is thrown upward with initial speed 15 m/s. Using g = 9.8 m/s^2, what is the maximum height reached?

Explanation:
Gravity slows the ball as it rises, and at the top its vertical speed becomes zero. Using v^2 = v0^2 − 2 g h with v = 0, the height is h = v0^2 / (2 g). With v0 = 15 m/s and g = 9.8 m/s^2, h = 225 / 19.6 ≈ 11.48 m, about 11.5 meters.

Gravity slows the ball as it rises, and at the top its vertical speed becomes zero. Using v^2 = v0^2 − 2 g h with v = 0, the height is h = v0^2 / (2 g). With v0 = 15 m/s and g = 9.8 m/s^2, h = 225 / 19.6 ≈ 11.48 m, about 11.5 meters.

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