A constant force of 8 N acts on an object for a displacement of 2 m in the same direction as the force. How much work is done?

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Multiple Choice

A constant force of 8 N acts on an object for a displacement of 2 m in the same direction as the force. How much work is done?

Explanation:
Work is the energy transferred when a force acts through a distance, and for a constant force the amount of work is W = F d cos(theta), where theta is the angle between the force and the displacement. Here the force and the displacement point in the same direction, so theta is 0 degrees and cos(0) = 1. That makes W = 8 N × 2 m × 1 = 16 joules. The positive value shows energy is being transferred to the object in the direction of the force. If the force were at an angle, you’d use the component along the motion (F cos theta) to compute the work.

Work is the energy transferred when a force acts through a distance, and for a constant force the amount of work is W = F d cos(theta), where theta is the angle between the force and the displacement. Here the force and the displacement point in the same direction, so theta is 0 degrees and cos(0) = 1. That makes W = 8 N × 2 m × 1 = 16 joules. The positive value shows energy is being transferred to the object in the direction of the force. If the force were at an angle, you’d use the component along the motion (F cos theta) to compute the work.

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