Which formula gives the range of a projectile neglecting air resistance?

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Multiple Choice

Which formula gives the range of a projectile neglecting air resistance?

Explanation:
Range in projectile motion tells you how far the projectile travels before it lands, assuming air resistance is neglected. The horizontal speed stays constant at v cos θ, while gravity governs the vertical motion. The time the projectile is in the air comes from vertical motion: it rises and falls, giving a total time T = 2 v sin θ / g. Multiplying horizontal speed by this time yields the range: R = (v cos θ) × (2 v sin θ / g) = v^2 sin(2θ) / g. Since sin(2θ) = 2 sin θ cos θ, this form makes perfect sense for all launch angles. The maximum range occurs at θ = 45°, giving R = v^2 / g, which is why that particular value often appears, but the general expression depends on the angle through sin(2θ). The other options don’t represent a distance correctly: one omits the angle dependence, and the others have incorrect units or form.

Range in projectile motion tells you how far the projectile travels before it lands, assuming air resistance is neglected. The horizontal speed stays constant at v cos θ, while gravity governs the vertical motion. The time the projectile is in the air comes from vertical motion: it rises and falls, giving a total time T = 2 v sin θ / g. Multiplying horizontal speed by this time yields the range: R = (v cos θ) × (2 v sin θ / g) = v^2 sin(2θ) / g. Since sin(2θ) = 2 sin θ cos θ, this form makes perfect sense for all launch angles. The maximum range occurs at θ = 45°, giving R = v^2 / g, which is why that particular value often appears, but the general expression depends on the angle through sin(2θ). The other options don’t represent a distance correctly: one omits the angle dependence, and the others have incorrect units or form.

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